site stats

C++ # is not followed by a macro parameter

WebThe rules (which did not change in C++11): Reserved in any scope, including for use as implementation macros: identifiers beginning with an underscore followed immediately by an uppercase letter identifiers containing adjacent underscores (or "double underscore") Reserved in the global namespace: identifiers beginning with an underscore WebNov 8, 2024 · You cannot use preprocessor conditional directives inside a macro. Generally speaking, the solution is to turn that inside out: use conditional directives to define the …

Can C/C++ preprocessor macros have default parameter values?

WebMar 31, 2015 · 1 #ifndef DEF_H 2 #define DEF_H 3 #define DEBUG_MODE 4 #define DEBUG_INFO (message) \ 5 #ifdef DEBUG_MODE \ 6 cout << message << endl; \ 7 … WebApr 10, 2024 · Macros are expanded by the preprocessor during preprocessing. c. #ifdef, #ifndef, #if, #else, #elif, and #endif: These directives are used for conditional compilation. They allow the preprocessor to include or exclude sections of code based on whether a certain macro is defined or not, or based on the value of an expression. Include Guards dating site for women trying to get pregnant https://p-csolutions.com

What are the rules about using an underscore in a C++ identifier?

WebJan 4, 2016 · Macros with Parameters (C++) navigation search Go Up to The Preprocessor Index The following syntax is used to define a macro with parameters: #define macro_identifier () Contents 1 Nesting Parentheses And Commas 2 Side Effects and Other Dangers 3 Converting Actual Arguments to … WebJan 17, 2024 · check whether the identifier is or is not currently defined as a macro name. Their conditions are equivalent to #if defined identifier and #if !defined identifier respectively. Then again if you are not sure what is the macro name and what are the parameters etc.. From standard §6.10.3.p10 A preprocessing directive of the form WebAug 2, 2024 · Each formal parameter in token-string that is not preceded by a stringizing ( # ), charizing ( #@ ), or token-pasting ( ##) operator, or not followed by a ## operator, is … bj\u0027s eastwood

how to use #ifdef inside a macro?

Category:error:

Tags:C++ # is not followed by a macro parameter

C++ # is not followed by a macro parameter

Macros with Parameters (C++) - RAD Studio - Embarcadero

WebMar 31, 2024 · How to redefine c++ macro with reduced parameters? Ask Question Asked 7 days ago Modified 5 days ago Viewed 54 times 0 I have following macros in an existing project, #define TRACE1 (attr,str,...) REL_LOG (attr, str, ##_VA_ARGS__) #define TRACE2 (str,...) REL_LOG (str, ##_VA_ARGS__) And they have been used like, WebJun 3, 2014 · The C preprocessor throws an error because the STATIC_ASSERT macro only takes one parameter. The two main solutions to this problem are to use double parentheses and, more recently, to use variadic macros: // Invoke the macro this way...

C++ # is not followed by a macro parameter

Did you know?

WebMay 17, 2024 · By defining a macro named CHECK_DEBUG we can change the result if the macro was not defined, e.g.:. godbolt. #define TEST CAT(CHECK_,DEBUG), 0, 1 … WebSep 26, 2024 · 1. I'm trying to write a macro that generates code for an object pool for any given class of objects in C. I keep getting error: '#' is not followed by a macro …

WebMar 1, 2012 · The C macro system cannot implicitly reference the parameters. You'd have to pass them to it. As a small win macros can count their arguments, so it would be TRACE (foo,bar) instead of TRACE2, TRACE3 etc. That's not significantly worse than writing TRACE () at the start of the function. Actually printing the values would be fine. WebAug 17, 2011 · This question describes a way to suppress the unused parameter warning by writing a macro inside the function code: Universally compiler independent way of implementing an UNUSED macro in C/C++ But I'm interested in a macro that can be used in the function signature: void callback (int UNUSED (some_useless_stuff)) {}

WebJan 4, 2016 · Such macros are called by writing. macro_identifier () in the subsequent source code. The syntax is identical to that of a … WebNov 20, 2024 · You can fix this with an extra "helper" macro: #define MAX_NAME_LEN 15 #define STRINGIFY (s) \ #s #define PRINT_CELL (x) \ printf (" %" STRINGIFY …

WebJan 25, 2024 · No, this is not possible. During translation, all preprocessing directives ( #define, #include, etc.) are executed before any macro expansion occurs, so if a macro expands into a preprocessing directive, it won't be interpreted as such - it will be interpreted as (invalid) source code. Share Improve this answer Follow answered Jan 24, 2024 at …

Webpasses two arguments to macro: array[x = yand x + 1]. If you want to supply array[x = y, x + 1]as an argument, you can write it as array[(x = y, x + 1)], which is equivalent C code. All … bj\\u0027s electric blanketWebOct 28, 2024 · Argument substitution expansion only occurs if the parameter in the macro corresponds to one in the replacement list (and that parameter isn't stringified with the # … bj\\u0027s employee websiteWebSep 25, 2015 · It's a pity that the defined operator is available only in the context of #if and #ifelse, but not for macro expansions. As it stands, I agree with rici about the solutions … bj\u0027s east rutherford nj gasolineWebMar 25, 2006 · C++ and C). By definition a macro (the part after the #define) ends on the same line. This can be partially ameliorated by the use of continuation lines (where the … bj\\u0027s electrical newtownWebJun 9, 2024 · You can define a variadic macro in C++ like: #define FOO (x, ...) bar (x, __VA_ARGS__) But calling FOO as FOO (1) results in the macro expansion bar (1,) which is obviously a syntactical error and won't compile. Therefore GCC includes a GNU extension: #define FOO (x, ...) bar (x, ##__VA_ARGS__) dating site france freeWebDec 12, 2013 · This won't work if I pass it a template that has more than one parameter, because the comma in the is interpreted as separating the macro arguments, … bj\u0027s eight o clock coffeeWebNov 19, 2024 · There are 2 problems with your macro definition: It uses incorrect syntax The name of a variable may be passed as a; in this case you cannot simply put the variable next to 2 string literals to do a concatenation. The latter problem can be solved by using a string and the + operator or simply using multiple printf s. dating site free australia